HDU - 1205-吃糖果 · znzryb
## 思路讲解
隔板法
如果说有maxA个挡板，至少要有maxA-1个数才能让隔板不相邻。
## AC代码
[https://vjudge.net/solution/60783771](https://vjudge.net/solution/60783771)
::: 源代码
```cpp
// Problem: 吃糖果
// Contest: Virtual Judge - HDU
// URL: https://vjudge.net/problem/HDU-1205
// Memory Limit: 32 MB
// Time Limit: 3000 ms
// by znzryb
//
// Powered by CP Editor (https://cpeditor.org)
#include <bits/stdc++.h>
#define all(vec) vec.begin(),vec.end()
#define CLR(i,a) memset(i,a,sizeof(i))
#define fi first
#define se second
#define pb push_back
#define SZ(a) ((int) a.size())
#define FOR(i, a, b) for (int i = (a); i <= (b); ++i)
#define ROF(i, a, b) for (int i = (a); i >= (b); --i)
#define getFro(vec) (vec.empty()?0:vec.front())
#define getBac(vec) (vec.empty()?0:vec.front())
#define debug(var) cerr << #var <<":"<<var<<"\n";
#define DEBUG(variable) \
do { \
std::cerr << #variable << ":"; \
for (const auto& elem : variable) { \
std::cerr << elem << " "; \
} \
std::cerr << "\n"; \
} while (0)
#define uniVec(var) \
do { \
sort(var.begin(),var.end());\
var.resize(unique(var.begin(),var.end())-var.begin());\
} while (0)
#define debugN(var,N) \
do{ \
std::cerr<<#var<<":"; \
FOR(i,1,N){ \
std::cerr<<var[i]<<" "; \
} \
std::cerr<<"\n"; \
}while(0)
#define debugMap(variable) \
do { \
std::cerr << #variable << ":\n"; \
for (const auto& pair : variable) { \
std::cerr << " " << pair.first << " => " << pair.second << "\n"; \
} \
std::cerr << std::endl; \
} while (0)
#define lson(var) (var<<1)
#define rson(var) ((var<<1)+1)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 i128;
typedef pair<ll,ll> pll;
typedef array<ll,3> arr;
typedef double DB;
typedef long double LD;
typedef pair<DB,DB> pdd;
typedef pair<ll,bool> plb;
constexpr ll MAXN=static_cast<ll>(1e6)+10,INF=static_cast<ll>(1e18)+3;
constexpr ll mod=static_cast<ll>(1e9)+7;
constexpr double eps=1e-8;
ll N,M,K,T,A[MAXN];
/*
*/
inline void solve(){
cin>>N;
ll sum=0,maxA=0;
FOR(i,1,N){
cin>>A[i];
sum+=A[i];
maxA=max(A[i],maxA);
}
// 如果说有maxA个挡板，至少要有maxA-1个数才能让隔板不相邻
if(sum-maxA<maxA-1){
cout<<"No\n";
}else{
cout<<"Yes\n";
}
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
cin>>T;
while(T--){
solve();
}
// solve();
return 0;
}
/*
AC
https://vjudge.net/solution/60783771
*/
```
:::
## 心路历程（WA，TLE，MLE……）