The 2025 Shanghai Collegiate Programming Contest - I. 真相(类似于树上背包的转移) · znzryb
## 思路讲解
递推公式。
```cpp
auto dfs=[&](auto&& self,ll u,ll p)->void{
dp[u][0]=1; // 每一个人说真话这种情况一定是存在的
for(auto &v:g[u]){
if(v==p) continue;
self(self,v,u);
vector<ll> tmp(N+5);
ROF(i,sz[u],0){
FOR(j,0,sz[v]){
tmp[i+j]+=dp[u][i]*dp[v][j]%mod;
tmp[i+j]%=mod;
}
}
dp[u]=tmp;
sz[u]+=sz[v];
}
// dp[u][A[u]-1] 就是如果u说真话,dp[u][A[u]]的值
// 因为u说真话,那么情况已经定下来了,其余的就是dp[u][A[u]-1]
dp[u][A[u]]=A[u]?dp[u][A[u]-1]:0; // 对于任何节点来说,A[u]=0都是悖论
};
```
## AC代码
[https://codeforces.com/gym/105992/submission/328455295](https://codeforces.com/gym/105992/submission/328455295)
::: 源代码
```cpp
// Problem: I. 真相
// Contest: Codeforces - The 2025 Shanghai Collegiate Programming Contest
// URL: https://codeforces.com/gym/105992/problem/I
// Memory Limit: 512 MB
// Time Limit: 1000 ms
//
// Powered by CP Editor (https://cpeditor.org)
#include <bits/stdc++.h>
#define all(vec) vec.begin(),vec.end()
#define pb push_back
#define SZ(a) ((int) a.size())
#define FOR(i, a, b) for (int i = (a); i <= (b); ++i)
#define ROF(i, a, b) for (int i = (a); i >= (b); --i)
#define debug(var) cerr << #var <<":"<<var<<"\n";
#define lson(var) (var<<1)
#define rson(var) ((var<<1)+1)
using namespace std;
using ll = long long;using ull = unsigned long long;
using DB=double;using LD=long double;
// using i128 = __int128;
using pdd = pair<DB,DB>;using plb = pair<ll,bool>;
using pll = pair<ll,ll>;
using arr3 = array<ll,3> ;using arr2 = array<ll,2>;
constexpr ll MAXN=static_cast<ll>(5e3)+10,INF=static_cast<ll>(1e17)+9; // 1e18+9也是素数
constexpr ll MAXM=(ll)1e6+10;constexpr ll MAXV=(ll)1e6+10;
constexpr ll mod= 998244353;
constexpr double eps=1e-8;const double pi=acos(-1.0);
ll N,M,Q,X,K,T,lT,A[MAXN];
/*
*/
inline void init(){
}
inline void solve(){
cin>>N;
init();
FOR(i,1,N){
cin>>A[i];
}
vector g(N+5,vector<ll>());
vector dp(N+5,vector<ll>(N+5));
FOR(i,1,N-1){
ll u,v;
cin>>u>>v;
g[u].pb(v);g[v].pb(u);
}
vector<ll> sz(N+5,1);
auto dfs=[&](auto&& self,ll u,ll p)->void{
dp[u][0]=1; // 每一个人说真话这种情况一定是存在的
for(auto &v:g[u]){
if(v==p) continue;
self(self,v,u);
vector<ll> tmp(N+5);
ROF(i,sz[u],0){
FOR(j,0,sz[v]){
tmp[i+j]+=dp[u][i]*dp[v][j]%mod;
tmp[i+j]%=mod;
}
}
dp[u]=tmp;
sz[u]+=sz[v];
}
dp[u][A[u]]=A[u]?dp[u][A[u]-1]:0;
};
dfs(dfs,1,1);
ll ans=0;
FOR(i,0,N){
ans+=dp[1][i];ans%=mod;
}
// #ifdef LOCAL
// FOR(i,1,N){
// FOR(j,0,N){
// cerr<<dp[i][j]<<" ";
// }
// cerr<<"\n";
// }
// #endif
cout<<ans<<"\n";
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
cin>>lT;
while(lT--)
solve();
return 0;
}
/*
AC
https://codeforces.com/gym/105992/my
*/
```
:::
## 心路历程(WA,TLE,MLE……)