2025“钉耙编程”中国大学生算法设计暑期联赛(1)——1003奸商 · znzryb
## 思路讲解
就是暴力枚举一下就行了。当然要预处理一下。
## AC代码
[https://acm.hdu.edu.cn/contest/view-code?cid=1172&rid=25007](https://acm.hdu.edu.cn/contest/view-code?cid=1172&rid=25007)
::: 源代码
```cpp
// Problem: 奸商
// Contest: HDOJ
// URL: https://acm.hdu.edu.cn/contest/problem?cid=1172&pid=1003
// Memory Limit: 262144 MB
// Time Limit: 1000 ms
// by Gospel_rock
//
// Powered by CP Editor (https://cpeditor.org)
#include <bits/stdc++.h>
#define all(vec) vec.begin(),vec.end()
#define pb push_back
#define EB emplace_back
#define EM emplace
#define FI first
#define SE second
#define SZ(a) ((int) a.size())
#define FOR(i, a, b) for (long long i = (a); i <= (b); ++i)
#define ROF(i, a, b) for (long long i = (a); i >= (b); --i)
#define debug(var) cerr << #var <<":"<<var<<"\n";
#define lson(var) (var<<1)
#define rson(var) ((var<<1)+1)
using namespace std;
using ll = long long;using ull = unsigned long long;
using DB=double;using LD=long double;
// using i128 = __int128;
using pdd = pair<DB,DB>;using plb = pair<ll,bool>;
using pll = pair<ll,ll>;using vll=vector<ll>;using vb=vector<bool>;
using tll = tuple<ll,ll,ll>;
using vpll = vector<pll>;
using arr3 = array<ll,3> ;using arr2 = array<ll,2>;
constexpr ll MAXN=(ll)3e3+10,INF=(ll)1e17+9; // 1e18+9也是素数
constexpr ll mod=(ll)1e9+7; // 998244353
constexpr double eps=1e-8;const double pi=acos(-1.0);
ll N,M,Q,X,K,T,lT,W[MAXN];
char S[MAXN];
/*
*/
inline void __(){
cin>>N;
FOR(i,1,N){
cin>>S[i];
}
FOR(i,1,17){
cin>>W[i];
}
ll len;cin>>len;
if(N==1){
cout<<0<<"\n";
return;
}
vll bits;
if(len%2==1){
len+=1;
}
if(len>N){
cout<<0<<"\n";
return;
}
// 可以先O(n*n)预处理一下
FOR(i,1,N){
bitset<20> bi;
bool ok=false;
FOR(j,1,N){
ll x=i-j+1,y=i+j;
if(x<1 || y>N) break;
#ifdef LOCAL
debug(x);debug(y);
#endif
if(S[x]!=S[y]){
bi[min(S[x],S[y])-'a']=true;
}else{
ok=true;
}
if(y-x+1==len){
if(ok) continue;
bits.pb(bi.to_ullong());
}
}
}
sort(all(bits));bits.resize(unique(all(bits))-bits.begin());
ll ans=INF;
#ifdef LOCAL
for(auto &b:bits){
bitset<20> bi(b);
FOR(i,0,17){
cerr<<bi[i];
}
cerr<<"\n";
}
FOR(i,0,17){
cerr<<char('a'+i);
}
cerr<<"\n";
FOR(i,1,17){
cerr<<W[i];
}
cerr<<"\n";
#endif
FOR(s,0,(1<<17)-1){
bitset<20> bi(s);
ll lans=0;
FOR(j,0,18){
if(bi[j]){
lans+=W[j+1];
}
}
if(lans>=ans) continue;
bool ok=true;
for(auto &b:bits){
// 这个字符串不需要幻视就是对的
if(b==0) continue;
if((s&b)==0){
ok=false;
break;
}
}
if(ok){
ans=lans;
}
}
cout<<ans<<"\n";
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
cin>>lT;
while(lT--)
__();
return 0;
}
/*
1
2
aa
1 1 8 3 4 4 8 4 2 4 6 8 9 8 2 2 8
2
ans:0
1
4
abbc
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
4
ans:0
AC
https://acm.hdu.edu.cn/contest/view-code?cid=1172&rid=25007
*/
```
:::
## 心路历程(WA,TLE,MLE……)