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CF2052A Adrenaline Rush

思路讲解

https://codeforces.com/contest/2052/submission/297107696

jianly的思路我觉得比官解更好(官解都看不懂是什么意思)

jianly的思路就是逆向思维,先将345612(这是输入进来的)转化为654321,再将654321转化为123456

整个过程我们都记录下来,reverse一下输出即可。

AC代码

https://codeforces.com/contest/2052/submission/311474567

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// Problem: CF2052A Adrenaline Rush
// Contest: Luogu
// URL: https://www.luogu.com.cn/problem/CF2052A
// Memory Limit: 1000 MB
// Time Limit: 3000 ms
// by znzryb
//
// Powered by CP Editor (https://cpeditor.org)

#include <bits/stdc++.h>
#define FOR(i, a, b) for (int i = (a); i <= (b); ++i)
#define ROF(i, a, b) for (int i = (a); i >= (b); --i)
#define all(x) x.begin(),x.end()
#define CLR(i,a) memset(i,a,sizeof(i))
#define fi first
#define se second
#define pb push_back
#define SZ(a) ((int) a.size())

using namespace std;

typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll,ll> pll;
typedef array<ll,3> arr;
typedef double DB;
typedef pair<DB,DB> pdd;
constexpr ll MAXN=static_cast<ll>(1e3)+10,INF=static_cast<ll>(5e18)+3;

ll N,M,C[MAXN];

inline void solve(){
cin>>N;
FOR(i,1,N){
cin>>C[i];
}
vector<pll> ans;
// 先将345612(这是输入进来的)转化为654321
ROF(i,N,1){
ll pi=0;
FOR(j,1,N){
if(C[j]==i){
pi=j;
break;
}
}
ROF(j,pi-1,1){
if(C[j]<C[j+1]){
// 不仅顺序最后要倒过来,超车顺序也要倒过来
ans.pb({C[j],C[j+1]});
swap(C[j],C[j+1]);
}
}
}
FOR(i,1,N){
FOR(j,i+1,N){
ans.pb({j,i});
}
}
reverse(ans.begin(),ans.end());
cout<<SZ(ans)<<"\n";
FOR(i,0,SZ(ans)-1){
cout<<ans[i].fi<<" "<<ans[i].se<<"\n";
}
// #ifdef LOCAL
// FOR(i,1,N){
// cerr<<C[i]<<" ";
// }
// cerr<<"\n";
// #endif
}

int main()
{
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
solve();
return 0;
}
/*
AC
https://codeforces.com/contest/2052/submission/311474567
*/

心路历程(WA,TLE,MLE……)